某程序的功能是a1<=q<a2,Shape1.FillColor = vbGreen;q<a4,Shape1.FillColor = vbRed
a2<=q<a3,Shape2.FillColor = vbGreen,Shape2.FillColor = vbGreen  ;q<a5,Shape2.FillColor = vbRed
a3<=q<15,Shape3.FillColor = vbGreen,Shape2.FillColor = vbGreen,Shape1.FillColor = vbGreen;q<a6,Shape3.FillColor = vbRed
我寫的程序存在的問題：shape1顯示正常，其余兩個顯示綠色沒問題，但若要顯示紅色不能顯示，任然是綠色，不發生變化。
Private Sub Command2_Click()
Const pi = 3.14159
Dim t As Single, y As Single, p As Single
Dim a1 As Single, a2 As Single, a3 As Single, a4 As Single, a5 As Single, a6 As Single, q As Single



a1 = Val(Text1.Text)
a2 = Val(Text2.Text)
a3 = Val(Text3.Text)
a4 = Val(Text4.Text)
a5 = Val(Text5.Text)
a6 = Val(Text6.Text)
For t = 0 To 24 Step 0.0003
y = -2 * Sin(t * pi / 1.5) + 3

p = y / 5
Text8.Height = Text7.Height * (1 - p)
q = p * 15
Text9.Text = q
Shape1.Refresh
DoEvents
Select Case q


Case 0 To a4
Shape1.FillColor = vbRed
Case a1 To a2
Shape1.FillColor = vbGreen


Case a4 To a5
Shape2.FillColor = vbRed
Case a2 To a3
Shape2.FillColor = vbGreen
Shape1.FillColor = vbGreen


Case a5 To a6
Shape3.FillColor = vbRed
Case a3 To 15
Shape3.FillColor = vbGreen
Shape2.FillColor = vbGreen
Shape1.FillColor = vbGreen


End Select
Next t
End Sub

Select Case 結構在滿足第一個條件后就自動跳到End Select。
而你的幾個CASE中有重疊部分，所以只會前者有效。
你可以試一下IF …Then

問題找到了,a1 = Val(Text1.Text),這樣的寫法，是取整數，而且 你設置的是有小數點

兩種解決問題，一就，你把所有數據都變大100倍，不要小數（好多似類的數量都是這樣數）

另外一種就，你把字符串，轉為FU點數

Dim a1 As Double
Dim a2 As Double
Dim K as double //定義水位
a2 = CDbl(Text1.Text)
a2 = CDbl(Text1.Text)
k = CDbl(水位的字符串)
if k <= a2 then
  Shape1.FillColor = vbRed
end if
if k >= a1 then
  Shape1.FillColor = vbGreen
end if

學習了

就例如，C水位，
如果當前水位在13.5-14之間，你如何顯示？？顯示綠色，還是紅色，這個在你上面的程序沒有處理。

謝謝各位了，非常感謝