1）、LRC 演算法校驗的實現

Public Function LRC(str As String) As String
c = 0
l = Len(str)
For c = c + 1 To l
c_data = Mid$(str, c, 2)
d_lrc = d_lrc + Val("&H" + c_data)
c = c + 1
Next c
If d_lrc > &HFF Then
    d_lrc = d_lrc Mod &H100
End If
h_lrc = Hex(&HFF - d_lrc + 1)

不好意思還有一點  接上面的

If Len(h_lrc) > 2 Then
     h_lrc = Mid(h_lrc, Len(h_lrc) - 1, 2)
End If
LRC = h_lrc
End Function